Section+1

__Vocabulary-__
 * Temperature-
 * An object is a measure of the average kinetic energy of the particles in the object.


 * Thermal Energy-
 * Sum of the kinetic energy and potential energy of all the particles.


 * Heat-
 * Thermal Energy that flows from something with a higher temperature to a lower temperature.


 * Specific Heat-
 * The amount of heat needed to raise the temperature of 1 kg by 1 degree Celsious.

__Self Check-__

Your hand particles run into the ice particles and transfer thermal energy, therefore moving energy and causing the ice to melt.
 * 1) 1- Explain-how energy moves when you touch a block if ice with your hand.

The thermal energy changes because the particles have more kinetic energy, the more kinetic energy you have the higher the temperature will be.
 * 1) 2- Describe-how thermal energy of an object changes when the object's temperature changes.

This is not true because the temperature change depends on what the exact specific heat of an object is.
 * 1) 3- Infer-when heat flows between two objects, does the temperature increase of one object always equal the temperature decrease of the other? Explain.

This is true because water is found to have stronger bonds and then this makes it so heat can not flow easily through the bonds.
 * 1) 4- Explain-why the specific heat of water is higher than the specific heat of most other substances.

Yes, this is true because the higher the temperature of an object the more thermal energy it has. This is because thermal energy is the total kinetic and potential energy of all the particles in an object, so therefor the thermal energy of the object increases when the average kinectic energy of its particles increases.
 * 1) 5-Think Critically- Explain wether or not the following statement is true: for any two objects, the one with the higher temperature always has more thermal energy.

__Applying Math-__

-1,000 kg x 4,184J/(kg*C) x- 1*C -4,184,000J
 * 1) 6- Calculate the change in thermal energy of the water in a pond with a mass of 1,000 kg and a specific heat of 4,184 J/(kg degrees celsious) if the water cools by 1 degree celsious.

Specific Heat- 0.5 kg 9,000 10 degrees C 9000/5 = 5x C/ 5 1800=C 1800J/(kg*C)
 * 1) 7- Calculate the specific heat of a metal if 0.5 kg of the metal absorb 9,000 J of heat as it warms by 10 degrees celsious.